28.62x^2-22.17+8.08=0

Solution for 28.62x^2-22.17+8.08=0 equation:

28.62x^2-22.17+8.08=0

We add all the numbers together, and all the variables

28.62x^2-14.09=0

a = 28.62; b = 0; c = -14.09;
Δ = b2-4ac
Δ = 02-4·28.62·(-14.09)
Δ = 1613.0232
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{1613.0232}}{2*28.62}=\frac{0-\sqrt{1613.0232}}{57.24}
=-\frac{\sqrt{}}{57.24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{1613.0232}}{2*28.62}=\frac{0+\sqrt{1613.0232}}{57.24}
=\frac{\sqrt{}}{57.24}
$